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Square Well Lines / Parallel caseParallel (par): Let the center of particle 1 be the origin of a cylindrical coordinate system, with particle 2 sitting at $(\rho, z)$. Considering only positive values of z, we find for the following ranges for $\rho$:
Given a position $\rho, z$ and a pair of internal points $\gamma, \delta$ we demand that $s^{2} \equiv \rho^{2}+ (z+\delta - \gamma )^{2}$ be smaller than $r_{2}$. For any given $\gamma$ this sets limits for $\delta$, which are the solutions of $ \delta^{2}+2\delta (z-\gamma )+(z-\gamma )^{2} - a^{2} = 0 $ where $a^{2}=r_{2}^{2}-\rho^{2}$. These solutions are $\delta = -(z-\gamma ) \pm a$. In other words, we have
$
\delta_{min} = \max [-h,\! -\!(z\!-\!\gamma )\! -\! a] \;\;\;\;
\delta_{max} = \min [ h, \!-\!(z\!-\!\gamma )\! +\! a]
$
For the extreme values of $\delta = \pm h$ we find four respective limiting values of $\gamma \,$:
$
\begin{eqnarray}
\gamma_{1}&=& \min(h,\max(\!-\!h,z\!-\!h\!-\!a))
\;\;\;\;
\gamma_{2}= \min(h,\max(\!-\!h,z\!+\!h\!-\!a))
\\
\gamma_{3}&=& \max(-h,\min( h,z\!-\!h\!+\!a))
\;\;\;\;
\gamma_{4}= \max(-h,\min( h,z\!+\!h\!+\!a))
\end{eqnarray}
$
Depending on the relative sizes of $\gamma_{2}$ and $\gamma_{3}$ we discern two cases: Case 1: $\gamma_{2} \leq \gamma_{3}$:
$
\begin{eqnarray}
u(1,2) & = &
\frac{\textstyle - \epsilon }{\textstyle L^{2}}
\left[
\int \limits_{\textstyle \gamma_{1}}^{\textstyle \gamma_{2}} d \gamma \,
[ \, h \! + \! a \! - \! z \! + \! \gamma \, ]
+ \, 2 h \int \limits_{\textstyle \gamma_{2}}^{\textstyle \gamma_{3}} d \gamma \,
+\int \limits_{\textstyle \gamma_{3}}^{\textstyle \gamma_{4}} d \gamma \,
[ \, h \! + \! a \! + \! z \! - \! \gamma \, ]
\right]
\\ & = &
\\ & = &
\frac{\textstyle - \epsilon }{\textstyle L^{2}}
\left[
( h \! + \! a \! - \! z )( \gamma_{2} \! - \! \gamma_{1} )
\! + \! ( \gamma_{2}^{2} \! - \! \gamma_{1}^{2} ) / 2
\! + \! 2 h \, ( \gamma_{3} \! - \! \gamma_{2} )
\! + \! ( h \! + \! a \! + \! z )( \gamma_{4} \! - \! \gamma_{3} )
\! - \! ( \gamma_{4}^{2} \! - \! \gamma_{3}^{2} ) / 2
\right]
\end{eqnarray}
$
Case 2: $\gamma_{2} > \gamma_{3}$:
$
\begin{eqnarray}
u(1,2) & = &
\frac{\textstyle - \epsilon }{\textstyle L^{2}}
\left[
\int \limits_{\textstyle \gamma_{1}}^{\textstyle \gamma_{3}} d \gamma \,
[ \, h \! + \! a \! - \! z \! + \! \gamma \, ]
+ \, 2 a \int \limits_{\textstyle \gamma_{3}}^{\textstyle \gamma_{2}} d \gamma \,
+\int \limits_{\textstyle \gamma_{2}}^{\textstyle \gamma_{4}} d \gamma \,
[ \, h \! + \! a \! + \! z \! - \! \gamma \, ]
\right]
\\ & = &
\\ & = &
\frac{\textstyle - \epsilon }{\textstyle L^{2}}
\left[
( h \! + \! a \! - \! z )( \gamma_{3} \! - \! \gamma_{1} )
\! + \! ( \gamma_{3}^{2} \! - \! \gamma_{1}^{2} ) / 2
\! + \! 2 a \, ( \gamma_{2} \! - \! \gamma_{3} )
\! + \! ( h \! + \! a \! + \! z )( \gamma_{4} \! - \! \gamma_{2} )
\! - \! ( \gamma_{4}^{2} \! - \! \gamma_{2}^{2} ) / 2
\right]
\end{eqnarray}
$
Alternatively, we may describe the pair in polar coordinates $(r, \theta)$. Three regions for $\theta$:
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